Optimal. Leaf size=107 \[ -\frac{2 e \cos (c+d x) \sqrt{a \sec (c+d x)+a} (1-\cos (c+d x))^{\frac{1-m}{2}} (\cos (c+d x)+1)^{-m/2} F_1\left (\frac{1}{2};\frac{1-m}{2},-\frac{m}{2};\frac{3}{2};\cos (c+d x),-\cos (c+d x)\right ) (e \sin (c+d x))^{m-1}}{d} \]
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Rubi [A] time = 0.313668, antiderivative size = 107, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.16, Rules used = {3876, 2886, 135, 133} \[ -\frac{2 e \cos (c+d x) \sqrt{a \sec (c+d x)+a} (1-\cos (c+d x))^{\frac{1-m}{2}} (\cos (c+d x)+1)^{-m/2} F_1\left (\frac{1}{2};\frac{1-m}{2},-\frac{m}{2};\frac{3}{2};\cos (c+d x),-\cos (c+d x)\right ) (e \sin (c+d x))^{m-1}}{d} \]
Antiderivative was successfully verified.
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Rule 3876
Rule 2886
Rule 135
Rule 133
Rubi steps
\begin{align*} \int \sqrt{a+a \sec (c+d x)} (e \sin (c+d x))^m \, dx &=\frac{\left (\sqrt{-\cos (c+d x)} \sqrt{a+a \sec (c+d x)}\right ) \int \frac{\sqrt{-a-a \cos (c+d x)} (e \sin (c+d x))^m}{\sqrt{-\cos (c+d x)}} \, dx}{\sqrt{-a-a \cos (c+d x)}}\\ &=-\frac{\left (e \sqrt{-\cos (c+d x)} (-a-a \cos (c+d x))^{-\frac{1}{2}+\frac{1-m}{2}} (-a+a \cos (c+d x))^{\frac{1-m}{2}} \sqrt{a+a \sec (c+d x)} (e \sin (c+d x))^{-1+m}\right ) \operatorname{Subst}\left (\int \frac{(-a-a x)^{\frac{1}{2}+\frac{1}{2} (-1+m)} (-a+a x)^{\frac{1}{2} (-1+m)}}{\sqrt{-x}} \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac{\left (e \sqrt{-\cos (c+d x)} (1+\cos (c+d x))^{-m/2} (-a-a \cos (c+d x))^{-\frac{1}{2}+\frac{1-m}{2}+\frac{m}{2}} (-a+a \cos (c+d x))^{\frac{1-m}{2}} \sqrt{a+a \sec (c+d x)} (e \sin (c+d x))^{-1+m}\right ) \operatorname{Subst}\left (\int \frac{(1+x)^{\frac{1}{2}+\frac{1}{2} (-1+m)} (-a+a x)^{\frac{1}{2} (-1+m)}}{\sqrt{-x}} \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac{\left (e (1-\cos (c+d x))^{\frac{1}{2}-\frac{m}{2}} \sqrt{-\cos (c+d x)} (1+\cos (c+d x))^{-m/2} (-a-a \cos (c+d x))^{-\frac{1}{2}+\frac{1-m}{2}+\frac{m}{2}} (-a+a \cos (c+d x))^{-\frac{1}{2}+\frac{1-m}{2}+\frac{m}{2}} \sqrt{a+a \sec (c+d x)} (e \sin (c+d x))^{-1+m}\right ) \operatorname{Subst}\left (\int \frac{(1-x)^{\frac{1}{2} (-1+m)} (1+x)^{\frac{1}{2}+\frac{1}{2} (-1+m)}}{\sqrt{-x}} \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac{2 e F_1\left (\frac{1}{2};\frac{1-m}{2},-\frac{m}{2};\frac{3}{2};\cos (c+d x),-\cos (c+d x)\right ) (1-\cos (c+d x))^{\frac{1-m}{2}} \cos (c+d x) (1+\cos (c+d x))^{-m/2} \sqrt{a+a \sec (c+d x)} (e \sin (c+d x))^{-1+m}}{d}\\ \end{align*}
Mathematica [B] time = 2.81868, size = 433, normalized size = 4.05 \[ \frac{4 (m+3) \sin \left (\frac{1}{2} (c+d x)\right ) \cos ^3\left (\frac{1}{2} (c+d x)\right ) \sqrt{a (\sec (c+d x)+1)} \left (F_1\left (\frac{m+1}{2};-\frac{1}{2},m+1;\frac{m+3}{2};\tan ^2\left (\frac{1}{2} (c+d x)\right ),-\tan ^2\left (\frac{1}{2} (c+d x)\right )\right )+F_1\left (\frac{m+1}{2};\frac{1}{2},m;\frac{m+3}{2};\tan ^2\left (\frac{1}{2} (c+d x)\right ),-\tan ^2\left (\frac{1}{2} (c+d x)\right )\right )\right ) (e \sin (c+d x))^m}{d (m+1) \left ((\cos (c+d x)-1) \left (2 (m+1) F_1\left (\frac{m+3}{2};-\frac{1}{2},m+2;\frac{m+5}{2};\tan ^2\left (\frac{1}{2} (c+d x)\right ),-\tan ^2\left (\frac{1}{2} (c+d x)\right )\right )+(2 m+1) F_1\left (\frac{m+3}{2};\frac{1}{2},m+1;\frac{m+5}{2};\tan ^2\left (\frac{1}{2} (c+d x)\right ),-\tan ^2\left (\frac{1}{2} (c+d x)\right )\right )-F_1\left (\frac{m+3}{2};\frac{3}{2},m;\frac{m+5}{2};\tan ^2\left (\frac{1}{2} (c+d x)\right ),-\tan ^2\left (\frac{1}{2} (c+d x)\right )\right )\right )+(m+3) (\cos (c+d x)+1) F_1\left (\frac{m+1}{2};-\frac{1}{2},m+1;\frac{m+3}{2};\tan ^2\left (\frac{1}{2} (c+d x)\right ),-\tan ^2\left (\frac{1}{2} (c+d x)\right )\right )+(m+3) (\cos (c+d x)+1) F_1\left (\frac{m+1}{2};\frac{1}{2},m;\frac{m+3}{2};\tan ^2\left (\frac{1}{2} (c+d x)\right ),-\tan ^2\left (\frac{1}{2} (c+d x)\right )\right )\right )} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.211, size = 0, normalized size = 0. \begin{align*} \int \sqrt{a+a\sec \left ( dx+c \right ) } \left ( e\sin \left ( dx+c \right ) \right ) ^{m}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{a \sec \left (d x + c\right ) + a} \left (e \sin \left (d x + c\right )\right )^{m}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\sqrt{a \sec \left (d x + c\right ) + a} \left (e \sin \left (d x + c\right )\right )^{m}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{a \sec \left (d x + c\right ) + a} \left (e \sin \left (d x + c\right )\right )^{m}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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